In the process A->B, 1500 J of heat are exchanged between the gas and the 20 surroundings, and in the process B->C, 4200 J of heat are exchanged A certain amount of ideal monoatomic gas undergoes, process given by UV112 = C where U is the internal energy of the gas. The gas is initially at a temperature of 133. It initially occupies 5 Lat atmospheric pressure and 347 K (point A in diagram above). What is the energy absorbed by heat into the gas during this process? Hint: The internal energy of a monatomic ideal gas at pressure P and occupying volume V is given by. (b) Change in the internal energy U of the Physics questions and answers. 00 m to 4. The ratio of change in internal energy and the work done by the gas is A. How is the pressure of the gas changed? p2/p1 =. and the initial one is 0. 314 J/mol ∙ K. Find the molar heat capacity of the gas as a function of V. 00 mol of an ideal monatomic gas initially at 300 K. (a) Calculate Remember how we found the entropy S(E, V, N) for a classical monatomic ideal gas? The hard part involved finding the volume of a shell in 3N-dimensional space. The gas will then undergo an isochoric process which A monatomic ideal gas undergoes the thermodynamic process shown in the PV diagram of the figure below. Report your answer as 'X' where Δ S s y s = X R l n 2 A monatomic ideal gas at 27. . What is the energy absorbed by heat into the gas during this process? the gas during this process? Hint: The internal energy of sure P and occupying volume V is given by U=(3)/(2) P V One mole of an ideal monoatomic gas is enclosed in a chamber at 300 K. Expert-verified. If its volume increases from V 1 to V 2, the amount of heat transfered to the gas is 100 m o l of an ideal monatomic gas undergoes the following thermodynamic process as shown in the figure (P − V or Pressure-Volume plots are shown) A → B: Isothermal expansion B → C: Adiabatic expansion C → D: Isobaric compression D → A Isochoric expansion The heat transfer along the process A B is 9 × 10 4 J. The process A B is isothermal and B C is isochoric. The gas is expanded from the initial volume of 1 L to final volume of 2 L starting from initial temperature of 273 K. A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are increased by a factor of n = 4 as shown in the figure below. 80, P2 = 3. The heat capacity of the gas during this process is: The heat capacity of the gas during this process is: A monatomic ideal gas at 27. There are 2 steps to solve this one. 0m asked Aug 1, 2019 in Physics by Satishkumar ( 25. 0 mol sample of an ideal monatomic gas originally at a pressure of 1 atm undergoes a 3-step process as follows: (i) It expands adiabatically from T1 = 588 K to T2 = 389 K. Total heat given to the gas during the process A B C is measured to be Q. An ideal diatomic gas occupies a volume V 1 at a pressure P 1 . At the end of the process, the volume of the gas is doubled. The molar specific heat of the gas for the process will be C = constantA. P P₂ atm BC P₁ atm 1 1 I V₁LV₂L where P₁ = 2. Solution. 0×103Pa and 𝛼=3. S t e p 3 - then expanded adiabatically to volume 80. An ideal monoatomic gas undergoes a process where its pressure is inversely proportional to its temperature. 3 RD. Then molar specific heat of gas in this process is: Then molar specific heat of gas in this process is: Apr 28, 2023 · 7. 9 m−3. There are 0. The gas undergoes a process in which the pressure is proportional to the volume. 501 m3. 0 moles of an ideal monoatomic gas undergo a process shown on the adjacent PV diagram. 27. One mole of an ideal, monatomic gas undergoes an isobaric process, an isochoric process, and an isothermal process. What is the entropy change of the gas? Here’s the best way to solve it. 4 K and volume of 0. The molar heat capacity of this gas during this process isA. The change in the internal energy of the gas is [ R is gas constant] Question: A monatomic ideal gas undergoes a quasi-static adiabatic expansion in which its volume is quadrupled. W =. B C PROBLEM 3: An ideal monoatomic gas undergoes the cycle shown. 29 m 3. It undergoes a process given by T = T 0 e α V, where T 0 and α are constants. Calculate Δ U, Δ H, Q, and W for each of the steps. 40, and V2 = 4. The pressure can be parameterized as a function of the volume following the relationship: P (V)= A(1+e−αV) where A= 70. If V1=2. Then it is cooled isochorically until the pressure is 1 MPa (step 2). A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are doubled as shown in the figure above. 3 R / 2B. One mole of a monoatomic ideal gas undergoes a cyclic process as shown in the figure where, V is the volume and T is the temperature . 5. This equation is the condition that must be obeyed by an ideal gas in a quasi-static adiabatic process. For an adiabatic compression we have p2 = p1(V1 V2)γ, so after the compression, the pressure of the mixture is p2 = (1. 13 R / 6C. p 1 V 1 γ = p 2 V 2 γ. A 1 P. 5 moles of an ideal monatomic gas undergo the series of processes shown in Figure 18–24. 2 R An ideal gas has a molar heat capacity C v at constant volume. How is the pressure of the gas changed? There are 2 steps to solve this one. The pressure can be parameterized as a function of the volume following the relationship: 𝑃 (𝑉)=𝐴 (1+𝑒−𝛼𝑉) where 𝐴=73. 60, V1 = 1. 2 moles of an ideal monoatomic gas undergoes a reversible process for which P 2 V = constant. 8×103 Pa and α =3. `-2000 R` Problem 10 An ideal monatomic gas undergoes the reversible cyclic process A-B-C-A shown in the PV diagram, where the initial temperature at the point A is 360 K, the pressure is 360 kPa and the volume is 10 L. 4 atm. The net work done by the gas during the cycle is [Take R = J K − 1 m o One mole of an ideal monoatomic gas expends isothermally against constant external pressure of 1 atm from initial volume of 1 L to a state where its final pressure become equal to external pressure. What is the work done by the gas? One mole of an ideal monoatomic gas undergoes the process as shown is the T-V indicator diagram. b: The gas then undergoes an isochoric process which takes it back to pressure p. (c) `1/3` D. IP Suppose 67. For example, if an ideal gas makes a quasi-static adiabatic transition from a state with pressure and volume p1 p 1 and V 1 V 1 to a state with p2 p 2 and V 2, V 2, then it must be true that p1V γ 1 = p2V γ 2. 20-26). 03 m3 to 0. Find `DeltaH` for the process : A. 40 mº). The gas is then compressed adiabatically back to the original state. . During this process the piston moves out A monoatomic ideal gas undergoes a process in which the ratio of P to V at any instant is constant and equal to unity. (Give your answer. The heat capacity of the gas during this process is: The heat capacity of the gas during this process is: Two moles of an ideal monoatomic gas undergo a cyclic process as shown in the figure. 00 m°, as shown in the figure (Figure 1) Part B What is the temperature at the end of this process? Th 325 K Figure 1 of 1 ous Answer 400 300 2200 100 Correct Part C Isotherm How much work is done by the gas during this expansion? 0 Question: A monatomic ideal gas undergoes a process that changes the pressure and volume of the gas and its container. At point B, Р the pressure, volume, and temperature are 20 atm, 1. If T 500 K, how much energy is transferred P by heat into the gas during the 1 22. A system consisting of 0. The molar heat capacity of gas is: The molar heat capacity of gas is: Q. What is the magnitude of the work done during this two step process? There are 2 steps to solve this one. a: The gas undergoes an isothermal compression to a final pressure of 5p. It undergoes an adiabatic expansion to a volume 4V at B, and is then heated at constant volume to C. (iii) It then returns to its original pressure and temperature by a constant volume process. (a) What is the final volume of the gas? (b) How much heat does the gas exchange during this process? One mole of an ideal gas with heat capacity at constant pressure C p undergoes the process T = T 0 + α V where T 0 and α are constants. 630 moles of the gas, and at point 1 , the temperature of the gas is −117∘C. The temperatures in different states are given as 6 T 1 = 3 T 2 = 2 T 4 = T 3 = 1800 K . During an adiabatic process, 20 moles of a monatomic ideal gas undergo a temperature change from 450 K to 320 K starting from an initial pressure is 400 kPa. 40, P2 = 2. Hint: The internal energy of a monatomic ideal gas at pressure P and occupying volume Vis given by ubev. `-600R` B. 20 m², PB = 2. R /2C. The number of moles is: 20. What is the change of the internal energy of the gas? What amount of heat flowed into the gas during the Jul 21, 2023 · 2 moles of an ideal monoatomic gas undergo a reversible process for which P V 2 = constant. If the initial temperature of the gas is 100K and the universal gas constant R = 8. A certain amount of a monoatomic ideal gas undergoes a process ρ U η= C, where ρ is the density of the gas and U is the internal energy. 2 moles of an ideal monatomic gas undergo an adiabatic compression from 0. Two moles of an ideal monatomic gas is taken through a cycle A B C A as shown in the P − T diagram. A certain amount of a monoatomic ideal gas undergoes a process ρ U η = C, where ρ is the density of the gas and U is the internal energy. 5 a) For each step identify its name and the initial and the final temperature. Sep 10, 2020 · Let’s take the thermodynamic limit of expression 2. 2 R A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are doubled as shown in Figure P12. See Answer. At constant temperature the pressure is doubled c. The gas is returned to STP via a constant-volume process. Then molar specific heat of gas in this process is: Then molar specific heat of gas in this process is: Q. 0 L, and 600 K, respectively. Calculate the change in specific entropy delta s if the expansion is isobaric. 01 m3 . Then, adiabatic compression to state C. For one mole of the monatomic ideal gas ΔU = 3/2R ΔT. Work equals the area under the graph P vs. May 25, 2018 · One mole of a monatomic ideal gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. (a) `3/2` B. It took us three or four hours to derive the Sackur-Tetrode formula (equation (2. The work needed can then be evaluated with W = ∫V2V1pdV. Afterwards, the gas is allowed to expand at a constant pressure (2 atm) back to half of its original volume. The gas undergoes a process in which pressure is proportional to the volume. A mono atomic ideal gas undergoes a process in which the ratio of P to V at any instant is constant and equals to 1, what is the molar heat capacity of the gas. 9MPa, what is V2 ? V2= L Your last answer was interpreted as follows: 1 Incorrect answer. For a mole of monatomic ideal gas X = 3 2 R ln (T T A) + Rln (V V A). Five moles of an ideal monoatomic gas undergo a constant pressure process at 190 kPa. The molar specific heat of the gas for the process will be (a) R/2 (b) 3R (c) 5R2 (d) -R/2 25 Choose the incorrect statement related to an icoharie nrana 34 W (a Hint: The internal energy of a monatomic ideal gas at pressure P and occupying volume V is given by U = 3/2 PV. The gas starts with volume V1 = 4 mº at pressure P1 = 1000 Pa and undergoes an isobaric process which reduces the volume to V2 = 2 m3. Heat absorbed by the gas in the process B C is An ideal monoatomic gas undergoes a process in which the gas volume relates to temperature as V T = c o n s t a n t. 80, V 1 = 2. Find the total work done on the gas during these two processes in Joules. The final volume is 0. Find the value of Δ S s y s for the above process. If volume of the system changes from $${ V }_{ 0 }\quad to\quad { 2V }_{ 0 }$$ then find the amount of heat transferred to the system One mole of a monoatomic ideal gas undergoes the process A → B in the given P V diagram. 6 days ago · One mole of an ideal monatomic gas undergoes a process described by the equation $P{{V}^{3}}=\text{ constant}$. 0x10 Pa and VB = 0. In the figure, n moles of a monoatomic ideal gas undergo the process A B C as shown in the P − V diagram. 0 m 3. What is the change in internal energy of the gas in this process, in terms of the initial pressure and volume? Question: g One m ole of a monatomic ideal gas at standard temperature and pressure (S TF) undergoes the following three processes: At constant pressure, the temperature is doubled. 12 (m) ^ (3). where P1 = 1. (4 pts) What is the initial and final volume of the gas? In a constant-volume process, 209 J of energy is transferred by heat to 1. Initially the gas is at temperature T 1, pressure P 1 and volume V 1 and the spring is in its relaxed state. Net heat flow One mole of an ideal gas undergoes a reversible isothermal compression from 10 L to 5 L. 4 mol of an ideal monoatomic gas undergoes a reversible process for which P V 2 = C. A certain amount of a monatomic ideal gas undergoes the process shown in the figure below, in which its pressure doubles and its volume triples. Determine the work done by the gas during the cycle. Report your answer as Y where ΔSsys = −Y RI n3. A thermodynamic process that lacks heat exchange between the system and its environment is called an 8. Which of the statements given below is are true? An ideal monoatomic gas undergoes a process where its pressure is inversely proportional to its temperature. A monatomic ideal gas undergoes a cyclic process as shown in the diagram above. S t e p 4 - then compressed isothermally May 31, 2019 · One mole of an ideal monatomic gas undergoes the following four reversible processes : Step 1 – it is first compressed adiabatically from volume `8. 00 × 105N / m2)(240 × 10 One mole of an ideal monoatomic gas undergoes a process described by the equation P V 3 = constant. At the end of process the root mean square speed of the gas molecules has doubled from its initial value then the heat supplied to the gas in the given process is Insight: The internal energy of a monatomic ideal gas depends only on the temperature of the gas. 2 L at a pressure of 2. equal to o. In terms of the number of moles,n, the initial pressure,Pi, and the initial volume,Vi, determine the following quantities. Question: A monatomic ideal gas undergoes a process that changes the pressure and volume of the gas. A 2. 2 atm (point C). During the process A B, pressure and temperature of the gas vary such that P T = c o n s t a n t, If T 1 = 300 K, calculate the work done on the gas is the process A B This equation is the condition that must be obeyed by an ideal gas in a quasi-static adiabatic process. A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are increased by a factor of n = 6 as shown in the figure below. The gas is initially held at a temperature of 122. R /2 One mole of a monatomic ideal gas undergoes a cyclic process as shown in the figure (where V is the volume and T is the temperature). 5 times the volume at a (Fig. 19 (m)^ (3). The system is carried through a cycle consisting of three processes: (i) The gas is heated at constant pressure until its volume is 4. 18. Measurements of the pressure find that the pressure can be parameterized as a function of thevolume following:P(V)=AV+BV2where A=1. 1. 37 L and P2=14. D- с V V. Which of the statements below is (are) true? Process I is an isochoric process; In process II, gas absorbs heat; In process IV, gas releases heat; Processes I and II are not isobaric Chemistry questions and answers. 4 L at point B. here the horizontal axis is ca Pes below and directly the es and line segments ward Correct Review Suppose 148 moles of a monatomic ideal gas undergo an isothermal expansion from 1. 0°C undergoes a constant volume process from A to B and a constant-pressure process from B to C. 11) An ideal monatomic gas undergoes the reversible expansion shown in Figure 18-1, where V2 = 5V1 and P2 = 3P1. Temperature at point 1 = 300 K and process 2-3 is isothermal. In an isothermal process the temperature remains constant, and therefore so does the internal energy. 3 J Hint: The internal energy of a monatomic ideal gas at pressure P and occupying volume V is given by U = 3/2 PV. What is the work done, the heat absorbed, the change of internal energy and the change of entropy in the process? (PA=0. Next, heat is extracted at a constant volume so that the pressure drops. 80, and V2 = 3. 0J mol –1 K –1, the decrease in its internal energy, in Joule, is. Here’s the best way to solve it. π/2 RC. 4 273 L atm m o l e − 1 Step 1. 50x10 Pa, Va= 0. `-1000 R` C. Then it is allowed to expand isothermally to 1 atm (point C) and at last compressed isobarically to its original state. An ideal monoatomic gas undergoes an expansion from state A to state B following a process which is shown in the indicator diagram. (ii) It is compressed at constant pressure until its temperature reaches T3 K. Find (a) the work done on the gas,(b) the increase in internal energy of the gas, and (c) its final temperature. For example, if an ideal gas makes a quasi-static adiabatic transition from a state with pressure and volume p 1 p 1 and V 1 V 1 to a state with p 2 p 2 and V 2, V 2, then it must be true that p 1 V 1 γ = p 2 V 2 γ. ___ J Two moles of a monatomic ideal gas at (5 MPa, 5 L) is expanded isothermally until the volume is doubled (step 1). An ideal monoatomic gas undergoes a process in which the gas volume relates to temperature as V T = c o n s t a n t. P0 = 8500 Pa. One mole of an ideal monatomic gas undergoes the following four reversible processes: S t e p 1 - it is first compressed adiabatically from volume 8. The heat capacity of the gas during this process is: Science. b. View Solution Q 4 A monatomic ideal gas undergoes a process that changes the pressure and volume of the gas and its container. 4k points) An ideal monoatomic gas undergoes a process in which the gas volume relates to temperature as V T = c o n s t a n t. 3/2 RB. a. 13 2. 00 mole of an ideal monatomic gas at STP first undergoes an isothermal expansion so that the volume at b is 2. 40, and V2 = 2. 5 R / 2D. The temperature drops in this process. 8K and One mole of an ideal monoatomic gas undergoes a cyclic process as shown in figure. 082 L a t m m o l − 1 K − 1 = 8. 00 mol sample of monoatomic ideal gas is take through the cycle shown. In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by T Δ X, where T is temperature of the system and Δ X is the infinitesimal change in a thermodynamic quantity X of the system. 29×105Pam6. 80, V₁ = 2. One mol of a monatomic ideal gas starts with volume V, at A. 4 L); then it expands isobarically to the state (P_0, 4V_0); and finally it is heated at a constant volume (isochorically) to (3P_0, 4V_0). The gas is now compressed isothermally until its volume is back to 5 L, but its pressure is now 2 MPa (step 3). (a) Work W done by the gas. The value of q is less than 0. As shown in the figure, a container with a moveable piston and containing a monatomic ideal gas in an initial state A undergoes an isovolumetric, then an isothermal, and finally an isobaric process to complete the cycle. For an ideal gas, the molar capacity at constant pressure Cp C p is given by Cp = CV +R = dR/2+ R C p = C V + R = d R / 2 + R, where d is the number of degrees of freedom of each molecule/entity in the system. 60. 0k points) 2 moles of an ideal monoatomic gas undergoes a reversible process for which P 2 V = constant. If initial temperature of gas is 300 K then total entropy change of system in the above process is: [ R = 0. The specific heat for this process isA. Question: Two moles of an ideal, monatomic gas undergoes the following reversible process: First, there is isothermal expansion from state A to state B. Determine the temperature and volume at the end of that step. Science. Then molar specific heat of gas in this process is: Then molar specific heat of gas in this process is: A monatomic ideal gas at 27. A monatomic ideal gas undergoes a quasi-static adiabatic expansion in which its volume is quadrupled. The gas is initially held at a temperature of 133. B 200 IV. AU ---Select-- Q ---Select- ---Select-- 2P 100 m o l e s of an ideal monatomic gas undergoes the thermodynamic process as shown in the figure A → B : isothermal expansion B → C : adiabatic expansion C → D : isobaric compression D → A : isochoric process The heat transfer along the process AB is 9 × 10 4 J. 37 m3 P0 = 10500 Pa. Pressure (Kilo-Pa) A ba 01 02 B Volume (m) A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are increased by a factor of n = 8 as shown in the figure below. Determine ∆U, W and Q for that step. May 25, 2019 · An ideal monoatomic gas undergoes a process in which its internal energy U and density `rho` vary as `Urho`= constant. 32 mol of a monatomic ideal gas, with occupies a volume of 2. Summary. Net work done by gas in complete cycle is The answer is 21 P1V1 but I don't really understand how to get this answer. Finally, a change in temperature of the gas at constant volume to bring it back to the original state, A. Given number of moles n = 2 mol change i …. 13 (the entropy of a finite system) to find the entropy per particle of an infinite monatomic ideal gas. `-3000 R` D. Consider an ideal gas that undergoes a reversible adiabatic expansion from an initial state, specified by known values V1 V 1 and T1 T 1, to a new state in which the value of the volume, V2 V 2, is known but the value of the temperature, T2 T 2, is not known. The initial pressure is: 400 k P a. Determine whether each of the values AU, Q, and W for the gas is positive, negative, or zero. T_0; A 1. RD. 40, P2 = 4. An ideal monoatomic gas undergoes a cyclic process ABCA as shown in the figure here heat absorbed during AB to the work done on the gas during BC is: 2V0---- 29 1) 21n2 2 in 2 ---- 3) 4 In 2 26 A A monatomic ideal gas undergoes a cyclic process as shown in the diagram above and initially occupies 5 L at atmospheric pressure and 322K it is heated at constant volume to three ATM then it is allowed to expand isothermal it to one ATM and that last compressed I still barely to it original state. Find the heat exchanged during the process (in L atm) R = 22. 86×105Pam3 and B=4. P (atm) B. 40, P 2 = 4. where P 1 = 2. (ii) The gas is cooled at constant volume until the pressure decreases to 1. 40, and V 2 = 4. 8K and volume of 0. It was found that the ratio r = Δ W Δ Q for the process was r = 2 / 3 . The temperature of the gas at A is T 0. 80. It is heated at constant volume to 3 atm (point B). The ideal gas constant is R = 8. The temperature goes from 20o C to 90o C. The first thing to do, in preparing to take the thermodynamic limit, is to write V V as vN, E v N, E as eN e N, and ΔE ∆ E as δeN δ e N so that the only size-dependent Sep 12, 2022 · Because we are modeling the process as a quasi-static adiabatic compression of an ideal gas, we have pVγ = constant and pV = nRT. V. 59m3 and increases to a volume of A certain amount of ideal monoatomic gas undergoes, process given by UV 1/2= C where U is the internal energy of the gas. DATA: V0 = 0. One mole of an ideal monoatomic gas undergoes a process described by the equation P V 3 = constant. find the value of ΔSsys for the above process. The gas sample is made to expand from an initial volume of 1 L to a final volume of 4 L starting from an initial temperature of 300 K. 0 m 3 to 1. The gas sample is made to expand from initial volume of 1 litre of final volume of 3 litre starting from initial temperature of 300 K. The gas is expanded from initial volume of 1 L to final volume of 3 L starting from initial temperature of 300 K. If the work done by two moles of gas if the temperature changes from T 1 t o T 2 is x R ( T 2 − T 1 ) . If initially during the expansion, the gas was absorbing heat and later on it was rejecting heat, then what was the volume of the gas when it started rejecting the heat? One mole of an ideal monoatomic gas undergoes a process described by the equation PV 3= constant. For an adiabatic reversible process, q = 0 A quantity of a monatomic ideal gas undergoes a process in which both its pressure and volume are doubled as shown in the figure above. Therefore, for the process from the initial state with P 1 V 1 = 3/2 RT 1 to the state with P,V,T the heat given to system is An ideal monatomic gas undergoes the following 4 processes: A (rapid compression), B, C (isothermal expansion), and D, as shown below. 0 mol sample of an ideal monatomic gas undergoes a reversible process at constant volume, increasing its temperature from 400 K to 600 K. An ideal monoatomic gas is confined in a horizontal cylinder by a spring loaded piston (as shown in the figure). 9m−3 . (a) Each state can be characterized . (b) `2/3` C. What is the change of the internal energy of the gas? 2 moles of an ideal monatomic gas undergoes the following process: it starts in the state (P_0 = 1 atm, V_0 = 2. 314 J/mol · K. Physics questions and answers. (d) `3/5` Feb 3, 2023 · A certain amount of an ideal monoatomic gas undergoes a thermodynamic process such that `VT^(2)=` constat where `V=` volume of gas, `T=` temperature o asked Jun 3, 2020 in Physics by AmaanYadav ( 89. 80, V1 = 1. A real gas has a specific heat close to but a little bit higher than that of the corresponding ideal gas with Cp ≃CV +R. A monatomic ideal gas at 27. Identify the constant value during the isobaric process, which is the pressure P, and recall that for an isobaric process d P = 0. U = 3/2PV. S t e p 2 - then expanded isothermally at temperature T 1 to volume 10. h) what is the heat absorbed by the gas Apr 16, 2020 · 2 mole of an ideal monoatomic gas undergoes a reversible process for which `PV^(2)=C`. The gas is then heated very slowly to temperature T 2, pressure P 2 and volume V 2. 20: Adiabatic Expansions of An Ideal Gas. Then molar specific heat of gas in this process is: Then molar specific heat of gas in this process is: Q<0 w>0 Deltas < 0 Delta U >0 a gas in a heat pump undergoes the steps shown for the gas the area enclosed by the lines represents the free energy change. Change in entropy net work done. It was found that the ratio r =Δ W /Δ Q for the process was r =2 / 3 . Physics. 5 R /2B. An ideal monatomic gas undergoes a reversible expansion from specific volume v_1 to specific volume v_2. Report your answer as 'X' where Δ S s y s = X R l n 2 Jul 10, 2019 · Where ΔU is the change in the internal energy of the gas; and W is work, done by the gas. 32)), namely An ideal monoatomic gas undergoes a process in which the gas volume relates to temperature as V T = c o n s t a n t. Find the total work done on the gas during these two processes. Please explain how this problem is done. 31. fb pq hb pw is vy ws oc ec qf